Question

A plane is flying at the height of 5000 m above the sea level. At a
Jarticular point, it is exactly above a submarine floating 1200 m below
the sea level. What is the vertical distance between them?​

Answer 1

Answer:

6200m

Step-by-step explanation:

the distance is 5000+1200= 6200

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Answer 2

$\huge{\bold{\underline{\underline{\:\:\:\: hello\: friend: - }}}} \\ \\\: \: \large{\bold{\underline{\underline{here \: is \: your \: answer: - } }}} \\ \\ \\ \sf \qquad \implies \: plane \: flying \: above = 5000 \: m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\\sf \qquad \implies \: plane \: flying \: below = - 1200 \: m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\\sf \qquad \implies \: vertical \: distnce =5000+ 1200 = \bf \: 6200 \: m \: \\ \\ \large{\bold{\underline{\underline{i \: hope \: this \: helps \: you \: }}}}$