A plane is flying with a constant speed along a straight line at an angle of 30°
with the horizontal. The weight of the plane is 100000 N and its engine provides
a thrust of 120000 N in the direction of flight. Two additional forces are exerted
on the plane: the lift force perpendicular to the plane’s wings, and the force due
to air resistance opposite to the direction of motion. Draw the free-body diagram
showing all forces on the plane. Determine the lift force and the force due to air
resistance.
Answers
Answered by
14
Answer:
Explanation:
Since the speed of plane is constant the net force on the plane will be zero and as shown in figure the lift force= 100000N and the air Resistance= 120000N
Attachments:
Answered by
18
The Lift force provided by wings is F = 86,600 N and the Resistance force is R = 70,000 N
Explanation:
- Weight of plane = 100000 N
- Thrust force provided by engine = 120000 N
To find:
The lift force "F" = ?
Force due to air resistance "R" = ?
Solution:
Lift force provided by the wings "F" = W cos (30°)
Lift force provided by the wings "F" = 100000 x 0.866
Lift force provided by the wings "F" = 86,600 N
T = Weight component down the slope + R
120000 = (100000 sin 30) + R
R = 120000 - 50000 = 70,000 N
Thus the Lift force provided by wings is F = 86,600 N and the Resistance force is R = 70,000 N
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