Question

A plane is inclined at angle of 30 degree with horizontal. Find the component of a force vector F=-10 K N perpendicular to the plane. Given that z- direction is vertically upward.

Answer 1

Answer:

(F)Force=-10k N

since z axis is vertically upward so the force is acting in vertically downward direction

If we draw a perpendicular to the plane the angle between the plane and the force is 30° so

Component of the force perpendicular to the plane=Fcos 30°=-10×√3/2

=-5√3N

Please mark the answer Brainliest!!