a plane left 30 min late then its scgeduled time and in order to reach the destination 1500km away in time it had to increase its speed by 100 km from the usual speed find usual speed
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Answered by
1
1500/x-1500/x+100=30/60
1500/x-1500/x+100=1/2-----equation
solve this equation bro..
u will get your answer
1500/x-1500/x+100=1/2-----equation
solve this equation bro..
u will get your answer
Simran0335:
Wht wil be the factors 100 and 7500
I think it is 75000. not 7500
wait
a'swer will be 500km/hr
when you will solve equation you will get x^2+100x-300000=0
on solving this equation you will get x=500kl/hr
km**
Thnxx bro..
it's OK
Answered by
0
Solution :-
Let the original speed of train be x km/hr
New speed = (x + 100) km/hr
We know that,
Time = Distance / Speed
Given : A plane left 30 minutes or 1/2 hours later than the scheduled time.
According to the question,
=> 1500/x - 1500/(x + 100) = 1/2
=> (1500x + 15000 - 1500x)/x(x + 100) = 1/2
=> 2(15000) = x(x + 100)
=> 30000 = x² + 100x
=> x² + 100x - 30000 = 0
=> x² + 600x - 500x - 30000 = 0
=> x(x + 600) - 500(x + 600) = 0
=> (x - 500) (x + 600) = 0
=> x = 500 or x = - 600
∴ x ≠ - 600 (Because speed can't be negative)
Hence,
Its usual speed = 500 km/hr
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