a plane left 30 minutes late due to its scheduled time and in order to reach the distance 1500 km away in time it to increase speed by 250 km per hour from the usual speed and the usual speed
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1
Usual speed=1500/30+250
=50+250m/s
=300m/s
=50+250m/s
=300m/s
Vaibhavtyagi2108:
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Answered by
1
1 hr = 60 min
1min = 1\60hr
30 min = 30\60 hr = 1\2 hr
let the usual speed be x
D = S*T
1500 = x * y
the speed is increased by 250
1500 = x +250 * y-30
from 1 and 2
x*y = x+250 * y-30
XY = XY - 30x + 250y - 7500
xy\xy = 250y -7500 -30x
0 = 250y -7500 -30x
7500 = 250y - 30x
1min = 1\60hr
30 min = 30\60 hr = 1\2 hr
let the usual speed be x
D = S*T
1500 = x * y
the speed is increased by 250
1500 = x +250 * y-30
from 1 and 2
x*y = x+250 * y-30
XY = XY - 30x + 250y - 7500
xy\xy = 250y -7500 -30x
0 = 250y -7500 -30x
7500 = 250y - 30x
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