.A plane left 40 minutes late due to bad weather and in order to reach its destination,
1600 km away in time, it had to increase its speed by 400 km/hr from its usual speed.
Find the usual speed of the plane
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Let the original speed be = x km / hr
we know that : time =speeddistance
As all the things are in hours (unit) we need to correct time in hours unit.
6040=32 hours
According to the question, x1600−x+4001600=32
(x)(x+400)1600x.640000−1600x×32
1920000=2x2+800x
2x2+800x−1920000=0
2(x2+400x−960000)=0
x2+400x−960000=0/2
x2+400x−960000=0
x2+1200x−800x−960000=0
x(x+1200)−800(x+1200)=0
(x−800)(x+1200)=0
x=80
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