Math, asked by eeeangel2010, 2 months ago

A plane loaded with cargo travels 2000 miles at an average speed of 400 Miles
per hour. On the return trip on the same route it travels at an average speed of
480 miles per hour. How much quicker was the return trip?
0 10 minutes
O 32 minutes
O 50 minutes
El
O 70 minutes
90 minutes​

Answers

Answered by Swarup1998
1

The return trip was 50 minutes quicker.

Correct option: 50 minutes

Step-by-step explanation:

Given, total distance = 2000 miles

Average speed (on trip) = 400 miles per hour

Time taken = distance ÷ speed

= 2000 ÷ 400 hours

= 5 hours

Average speed (on return trip) = 480 miles per hour

Time taken = distance ÷ speed

= 2000 ÷ 480 hours

= 4 hours 10 minutes

So, the return was quicker by (5 hours - 4 hours 10 minutes) = 50 minutes.

#SPJ3

Answered by writetoaditig
0

Answer:

If a plane travels at a speed of 400 miles/hr for a distance of 2000 miles then it would take the (2000/400=5) hours to reach the destination.


If a plane travels at a speed of 480 miles/hr for a distance of 2000 miles then it would take the (2000/480=4.1) hours to reach the destination that is 4 hours 10 mins.

The difference between the times taken by both of planes is our answer.


5 hours - 4 hours 10 mins = 50 Minutes

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