Question

A plane moving with velocity v turns by 'θ' angle and its velocity remains same, Find the change in velocity of plane.​

Answer 1

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resultant velocity by using law of cosine

$resultant \: velocity \\ = ( {v}^{2} + {v}^{2} + 2 {v}^{2} cos \theta)^{ \frac{1}{2} }$

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Answer 2

Answer:

Since, magnitude of velocity, i.e speed is constant, this not change in magnitude of velocity

∴ magnitude of change in velocity,

➳ |vf - vi|

➳ √v² + v² - 2.v . v . Cosϴ

➳ v√2(1- cosϴ)

Now, 1 - cos2ϴ = 2sin²ϴ

➳ 1 - cosϴ = 2sin² ϴ)2

Thus magnitude of change in velocity

=> √4 sin² ϴ/2 = 2v sin(ϴ/2)

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