Question

if a and b satisfy the equations 3x+7y=5 and 11x+5y=7 then 31(a+b)​

Answer 1

I hope this is the answer .. Thank you ..

Answer 2

Answer:

Step-by-step explanation:

3x+7y=5

3a+7b=5 -------(1)

11x+5y=7

11a+5b=7 -------(2)

Solving (1) & (2)

(3a+7b=5)×11

(11a+5b=7)×3

33a+77b=55

33a+15b=21

___________

62b=34

b=17\31

Putting b value in equation (1)

We get a=12\31

31(a+b)

31(12/31+17/31)

31(12+17/31)

31(29/31)

29

Hence proved