Question

A plane polarized electromagnetic wave travelling in a dielectric medium of refractive index n is reflected at normal incidence from the surface of a conductor. Find the phase change undergone by its electric field vector if the refractive index of the conductor is n2 = n(1 + iρ)

Answer 1

Answer:

327.5∘.

Explanation:

A plane wave is travelling in a dielectric medium with a refractive index n1=nn1=n and is reflected at normal incidence from the surface of a conductor with complex refractive index

n2=n(1+jπ).n2=n(1+jπ).

The phase change undergone by its electric vector is equal to the phase of the reflection coefficient at the interface

Γ=n1−n2n1+n2=−jnπn(2+jπ)=−j2π−π24+π2.Γ=n1−n2n1+n2=−jnπn(2+jπ)=−j2π−π24+π2.

Therefore the phase change equal to

Φ=tan−1(Im(Γ)/Re(Γ))=tan−1(−2/π)≈327.5∘.

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