Question

A plane progressive wave of frequency 50Hz traveling along positive x-axis is representing as y=5*10-5 sin (100πt) at x=0. Wave speed is 300m/s. The value of 2π\ Lamda, is​

Answer 1

Answer:

π/3

Explanation:

GIVEN:

v=300m/s

n=50Hz

TO FIND:

2π/lambda

SOLUTION:

Since,v=n*lambda

lambda=v/n=300/50=6

Therefore,2π/lambda=2π/6=π/3

Answer 2

The value of 2π\ Lambda is 1.04719.

Explanation:

Given,

               frequency of wave is 50 Hz along positive x-axis.

                representing wave, y = $5^{10} - 5 Sin (100\pi t)$ at x = 0

                Wave speed 'v' = 300 m/s

                     

Now, we know the basic equation,

                                    ⇒ y = a Sin 2π nt

Compare this equation from given equation. We get,

                                    a = $5^{10}$

                                    n = 50

We know that,

                            ⇒      λ = $\frac{v}{n}$

                            ⇒   λ = 6 m

So,

                             

                            ⇒ $\frac{2\pi }{Lambda}$ = 1.04719 m