Math, asked by viveksaini491, 10 months ago

£fi=18,£fixi =2p+24 and mean of any distribution is 2,then p is equal to​

Answers

Answered by MaheswariS
1

\underline{\textbf{Given:}}

\mathsf{\sum\,f_i=18,\;\sum\,f_ix_i=2p+24\;and\;mean=2}

\underline{\textbf{To find:}}

\textsf{The value of p}

\underline{\textbf{Solution:}}

\boxed{\mathsf{Mean=\dfrac{\sum\,f_ix_i}{\sum\,f_i}}}

\implies\mathsf{2=\dfrac{2p+24}{18}}

\implies\mathsf{36=2p+24}

\implies\mathsf{36-24=2p}

\implies\mathsf{2p=12}

\implies\mathsf{p=\dfrac{12}{2}}

\implies\textbf{p=6}

\underline{\textbf{Answer:}}

\textbf{The value of p is 6}

\underline{\textbf{Find more:}}

Find the mean of the following distribution table class interval 5–15 15―25 25―35 35―45 45―55 55 ―65 frequency are 6 11 21 23 14 5  

https://brainly.in/question/8085025  

Answered by arij75
0

Given :

£fi = 18 l, £fixi = 2p + 24, mean = 2

mean = £fixi/£fi

2 = 2p + 24 / 18

36 = 2p + 23

36 - 24 = 2p

12 = 2p

p = 12/2

= 6

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