Question

A plane starting from rest accelerates at 5m/s2 to its takeoff velocity in 15s. The takeoff velocity of the plane is ? m/s

Answer 1

using v = u + at
you get final velocity v = 0 + 5 * 15
                                       = 75 m/s

Answer 2

U=0 & a=5 m/s^2 given t=15min v-u=at solving we get v=75m/s^2