Question

A plane wall has a thermal conductivity of 2 W/m-K. If the inner surface is at 1100 deg C and the outer surface is at 350 deg C, then what is the the design thickness (in meter) of the wall to maintain a steady heat flux of 2500 W/m^2.​

Answer 1

Answer:0.6 m

Explanation:rate of flow of heat dQ/dt =Ak(deltaT)/ l

Now heat flux is cons per unit area= 2500

Thus (dQ/dt)/A=2500

k=2

Delta T =750

Thus l=0.6m