Physics, asked by heartlessqueen1425, 11 months ago

A planet of mass 3 × 1026 kg moves around a star with a constant speed of 2 × 106 ms1 in
a circle of radius 1.5 × 1012 m. The gravitational force acting on the planet is

Answers

Answered by SUBRATA4322
0

Answer:

PHYSICS

A planet of mass 3×1029 gm moves around a star with a constant speed of 2×108ms−1 in a circle of radii 1.5×1012m. The gravitational force exerted on the planet by the star is

A .

6.67×1022 dyne

B .

6.67×1026 N

C .

8×1026 N

D .

8×1027 dyne

ANSWER

Gravitational force supplies centripetal force

∵F=rmv2=1.5×10143×1029×(2×108)2 dynes

=8×1031 dyne =8×1026N(∵1N=105 dyne. )

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