Question

A plant with genotype ab/ab is crossed with Ab/ab Plant. in this cross 1800 out od 3000 individual are parental type . then the distance between a and b gene is ? 1) 40 map unit 2) 60 map unit 3)20 map unit 4)18 map unit​

Answer 1

Answer:

2

Explanation:

correct answer is 2 - 60 map unit

Answer 2

Total no. of offspring’s = 3000
No. of parental types = 1800
No. of recombinants = 1200

Recombination frequency = (No. of recombinants/ Total no. of offsprings) x 100
= (1200/3000)x100 = 40 map units [option 1]