Question

a plastic box 1.5 m long and 1.25 m wide and 65 cm deep determine the thickness of the plastic sheet (1) the area of the sheet required for making the box​

Answer 1

Answer:

Given:

Length of box =1.5 m, Breadth =1.25 m, Height =0.65 m

⇒Area to be white-washed = Area of cuboid − Area of base.

(i) Area of sheet requred =2lb+2bh+2lh−lb

(i) Area of sheet requred =2lh+2bh+lb .....[Box is open]

=[2×1.5×0.65+2×1.25×0.65+1.5×1.25] m

=(1.95+1.625+1.875)m

=5.45 m

ii) Cost of sheet per m

area = Rs. 20

Cost of sheet of 5.45m

area = Rs. 5.45×20

= Rs. 109

Thankyou,

Solved By

Aaditya Singh

Answer 2

given :-

• Length = 1.5m
• Breadth = 1.25m
• Depth (h) = 0.65m

Solution :-

(i) box is to be open at top.

Area of sheet required

= (2lh + 2bh + lb)

= [2×1.5×0.65 +2×1.25×0.65 +1.5×1.25]

= [1.95 + 1.625 + 1.875 ]${m}^{2}$

= 5.4 ${m}^{2}$

(ii) cost of sheet per ${m}^{2}$ ?

cost of sheet per ${m}^{2}$ = Rs 20

cost of sheet of 5.45${m}^{2}$ = 5.45×20

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= Rs 109