Math, asked by karishmajubish, 9 months ago

A plastic box 1.5m long,1.25m wide and 65cm deep is to be made . It is opened at the top. lgnoring the thickness of the plastic sheet, determine:
a) The area of the sheet required for making the box.

Answers

Answered by Anonymous
6

Answer:

Given:

  • A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made.
  • It is opened at the top, Ignoring the thickness of the plastic sheet, determine.

Find:

  • The area of the sheet required for making the box.

Know terms:

  • l = length.
  • b = breadth

Calculations:

= 2 lb + 2 lb + 2 lb

= 2 (1.5) (1.25) + 2 (1.5) (0.65) + 2 (1.5) (0.65)

= 1.95 + 1.625 + 1.875

= 5.45²

Therefore, 5.45 cm² is the area of the sheet required for making the box.

Answered by Anonymous
3

Given :

Length of box (l) = 1.5 m

Breadth of box (b) = 1.25 m

Depth of box (h) = 65 cm = 0.65 m

To Find :

We have to find the area of the sheet required for making the box ?

Explanation :

We know that,

\large{\star{\underline{\boxed{\sf{Area = 2(lb + bh + lh)}}}}}

As, box is opened from the. So, we wiol subrtract the upper side.

Then, the formula becomes

\large{\star{\underline{\boxed{\sf{Area = 2(lb + bh + lh) - lb}}}}}

\sf{\dashrightarrow Area = 2(lb) + 2(bh) + 2(lh) - lb} \\ \\ \sf{\dashrightarrow Area = lb + 2bh + 2lh} \\ \\ \sf{\dashrightarrow Area = 1.5(1.25) + 2(1.25)(0.65) + 2(1.5)(0.65)} \\ \\ \sf{\dashrightarrow Area = 1.95 + 1.625 + 1.875} \\ \\ \sf{\dashrightarrow Area = 5.45} \\ \\ \large{\star{\underline{\boxed{\sf{Area = 5.45 \: m^2}}}}}

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