Question

A plate of dimensions 3l 5l on heating %
change in area is 2%. A change in the
volume of a metal cube of same material
of dimension 51 61 71 on heating to
double the raise in temperature of the
plate​

Answer 1

Answer:

6%

Explanation:

DeltaAA=Beta*Delta t and Delta VV=y*2Delta t=Delta VV=6%