A platform 10m by 10m has been built around a well which has a diameter of 5.6m .find the cost of cementing the platform at the rate of ruppes 25per sq.m (use π=22/7
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37
Area of circle = 22/7 * r^2
= 22/7 * 2.8^2
=22/7 * 7.84
=172.48/7 = 24.64sqm
Area of square = a^2
=10*10 = 100sqm
Area to be cemented = 100 - 24.64 = 75.36 sqm
Cost of cementing 75.36sqm = 25 * 75.36
= ₹1884
= 22/7 * 2.8^2
=22/7 * 7.84
=172.48/7 = 24.64sqm
Area of square = a^2
=10*10 = 100sqm
Area to be cemented = 100 - 24.64 = 75.36 sqm
Cost of cementing 75.36sqm = 25 * 75.36
= ₹1884
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3
1884 is the right answer
Step-by-step explanation:
1884
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