A play ground is in the shape of the rectangle find the perimeter of the rectangular play ground if its length is twice its breadth and area is2048 sq m
Answers
Answered by
1
let breadth = x
according to the question breadth =2x
we know that area = lenght x breadth
=> x × 2x =2048
=> 2 x^2 = 2048
=> x^2 =2048/2
=> x = root over of 1024 = 32m
so lenght = twice x
2 x 32
= 64
perimeter = 2x (l+b)
= 2 ×( 32 + 64)
:::::: = 2× 96
= 192
according to the question breadth =2x
we know that area = lenght x breadth
=> x × 2x =2048
=> 2 x^2 = 2048
=> x^2 =2048/2
=> x = root over of 1024 = 32m
so lenght = twice x
2 x 32
= 64
perimeter = 2x (l+b)
= 2 ×( 32 + 64)
:::::: = 2× 96
= 192
Answered by
2
Let the length be 2x and breadth be x
A/Q
2x*x=2048
2x^2=2048
x^2=2048/2
x^2=1024
x=✓1024
x=32
hence l=2x=64
b=x=32
perimeter of rectangle = 2(l+b)
=2*(64+32)
2*96
=192 Ans
Hope this will help you
A/Q
2x*x=2048
2x^2=2048
x^2=2048/2
x^2=1024
x=✓1024
x=32
hence l=2x=64
b=x=32
perimeter of rectangle = 2(l+b)
=2*(64+32)
2*96
=192 Ans
Hope this will help you
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