A solid toy is in the form of right circular cylinder with cone shape at one end ,there common diameter is 12cm ,and the height of the toy and conical portions are 21cm and 8cm respectively.find tsa of toy
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Solution :-
Height of the conical portion = 7 cm and height of the cylindrical portion = 12 cm
Radius = Diameter/2
= 4.2/2
= 2.1 cm
Volume of the solid toy = Volume of the conical portion + Volume of the cylindrical portion + Volume of the hemispherical portion
⇒1/3πr²h + πr²h + 2/3πr³
⇒ (1/3*22/7*2.1*2.1*7) + (22/7*2.1*2.1*12) + 2/3*22/7*2.1*2.1*2.1
⇒ 679.14/21 + 1164.24/7 + 407.484/21
⇒ (32.14 cu cm) + (166.32 cu cm) + (19.404 cu cm)
⇒ 217.864 cu cm
Answer.
Height of the conical portion = 7 cm and height of the cylindrical portion = 12 cm
Radius = Diameter/2
= 4.2/2
= 2.1 cm
Volume of the solid toy = Volume of the conical portion + Volume of the cylindrical portion + Volume of the hemispherical portion
⇒1/3πr²h + πr²h + 2/3πr³
⇒ (1/3*22/7*2.1*2.1*7) + (22/7*2.1*2.1*12) + 2/3*22/7*2.1*2.1*2.1
⇒ 679.14/21 + 1164.24/7 + 407.484/21
⇒ (32.14 cu cm) + (166.32 cu cm) + (19.404 cu cm)
⇒ 217.864 cu cm
Answer.
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