Question

a player caught a cricket ball of mass 150 gm moving at a rate of 20 metre per second if the catching process be completed in 0.1 seconds then the force of the blow exerted by the ball on the hand of the player is

Answer 1

30N

Explanation:

∆p=m(v-u)

=150/1000(0-20)

=-3Ns

∆p=I

f =I/∆

= -3/0.1

=30N