Question

A PLAYER KICKS A BALL AT AN ANGLE OF 37 TO THE HORIZONTAL WITH AN INITIAL SPEED OF 15 m/s. FIND ITS TIME OF FLIGHT??

Answer 1

Answer:

Explanation:

Angle = 37

U= 15 m/s

We know time = 2uSintheta /g

Putting it in formula we get

=30 × Sin37 /10

=9/5 m

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