Question

A player kicks up a ball at an angle θ to the horizontal. The horizontal range is maximum when θ equals

Answer 1

horizontal range is =u^2sin2theta/g

Answer 2

∅ = 45°

Explanation:

the maximum range of a projectile is

R(max) = $\frac{\left(u^2sin2\theta \right)}{g}$

where:

• u = initial velocity

• g = acceleration due to gravity
• ∅ = angle of elevation (angel at which the ball is kicked)

In order to get the maximum value for range, sin2∅ must have the largest value possible (since u and g are constant, we neglect these values)

maximum attainable value of sin∅ is 1

∴ sin(2∅) = 1

we know that sin(90°) = 1

thus, 2∅ = 90

         ∅ = 45°