Math, asked by shubh25365, 1 year ago

find the roots of the quadratic equation (x-1)/(x-2)+(x-3)/(x-3)=4

Answers

Answered by lakshit12
0

(x - 1) \div (x - 2) + 1 = 4  \\ multiplying \: all \: equation \: with \: (x - 2) \\ (x - 1)(x - 2) - 3(x - 2)   = 0 \\  (x) {}^{2}  - 3x + 2 = 0 \\ x {}^{2}   - 2x - x + 2 = 0 \\ x(x - 2) - 1(x - 2) = 0 \\ (x - 2)(x - 1) = 0 \\ so \: x = 1 \: and \: x = 2 \\ are \: roots \: of \: the \: equaions
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