A player moves along the boundary of a square ground of side 50 m in 200 sec.The magnitude of displacement of the farmer at the end of 11 minutes 40 seconds from his initial position is
Answers
Hi friend,
Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
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Answer:
Answer = √5000 m
Explanation:
Because,
= A square has all sides equal.
Given :
[ See the below given picture for get some idea or clarity about the question ]
= Side (a) = 50 m
= Perimeter of a square = 4a unit
= 4* 50 = 200 m
= Speed = Distance / Time = m/s (S.I Unit)
= 200 m/200 s
= 1 m/s( Speed)
Question:
Time=11 minutes 40 seconds
[We are going to convert this time to seconds for better understanding.]
1 min= 60 seconds
=(11*60)+40 s
=660+40 s
=700 s
Therefore, We got the time.With this we can get our distance.
As,we have seen already that the player moves in the speed of 1 m/s.
D=S*T
=1*700 s
D= 700 s
That is,the player has covered 3 and half rounds.
1 round= 200 m
3.5 round= 200*3.5 m
=700 m
As,Displacement is the shortest distance between initial and final position,AC is the displacement in given question(Refer below given image.)
To find displacement in a square path we can use pythagoras theorem.
{ Pythagoras Theorem :
AC² = AB² + BC² }
AC² = 50² + 50²
= 2500 + 2500
= 5000
AC= √5000 m
