A player moves along the boundary of a square ground of side 50m in 200 sec . The magnitude of displacement of farmer at the end of 11 minutes 40 second from his initial position is
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7
Answer:
The displacement at the end of 11mins 40sec from its initial point is 50√2m.
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Answered by
3
Answer:50√2m
Explanation:
after 600 sec he will be at the initial position so in next 100 sec he will cover 2 sides of the square and now he is at diagonally opposite point to initial position
so displacement =√((50)^2+(50)^2)
|| =50√2
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