Physics, asked by ashwamedh22, 8 months ago

A player moves along the boundary of a square ground of side 50m in 200 sec . The magnitude of displacement of farmer at the end of 11 minutes 40 second from his initial position is​

Answers

Answered by shizuka0003
7

Answer:

The displacement at the end of 11mins 40sec from its initial point is 50√2m.

Hope it helped you...

Answered by erenjoseph
3

Answer:50√2m

Explanation:

after 600 sec he will be at the initial position so in next 100 sec he will cover 2 sides of the square and now he is at diagonally opposite point to initial position

so displacement =√((50)^2+(50)^2)

|| =50√2

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