a player stops a cricket ball of mass 0.170kg in 1/4 by exerting a force 16.65N with what velocity was the ball moving
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Answer:
Mass of ball, m = 0.170 kg
Force applied to stop the ball, F = -16.65 N
time taken to stop the ball, t = 1/4 sec
final velocity of ball, v = 0 m/s
F = ma
-16.65 = 0.17 × a
a = -97.9 m/s²
v = u + at
0 = u + -97.9 × 1/4
u = 24.475 m/s
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