Question

A player throws a die. If a 3 or a 5 is obtained, he wins Php100. If a 1, 2, 4, or 6, he loses Php30. If he continues to play the game, will he expect to win or lose in the game?A player throws a die. If a 3 or a 5 is obtained, he wins Php100. If a 1, 2, 4, or 6, he loses Php30. If he continues to play the game, will he expect to win or lose in the game? by how much? (Express to the nearest hundredths.)

Answer 1

Answer:

pls tell this answer simplify 4 2/3 + 3 1/4

Answer 2

We recall the concept of probability.

Probability has a meaning as a possibility

Given:

If a  $3 or 5$is obtained, he wins Php100. If a $1,2,4,or6$, he loses Php30.

P(winning)$=\frac{2}{6}$

                $=\frac{1}{3}$

  P(losing)$=\frac{4}{6}$

                $=\frac{2}{3}$

P(losing)>P(winning)

Hence he expects to lose in the game