A player with 3 m long iron rod runs towards east with a speed of 30 km/hr. Horizontal component of earth's magnetic field is 4×10⁻⁵ Wb /m². If he is running with rod in horizontal and vertical positions, then the potential difference induced between the two ends of the rod in two cases will be
(a) Zero in vertical position and 1×10⁻³ V in horizontal position(b) 1×10⁻³ V in vertical position and zero is horizontal position
(c) Zero in both cases(d) 1×10⁻³ V in both cases
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length of rod , l = 3m
speed of player , v = 30 km/h = 30 × 5/18 = 25/3 m/s
horizontal component of earth's magnetic field, B , = 4 × 10^-5 T
if the player is running with rod in vertical position towards east then, rod cuts earth magnetic field { as you know, earth's magnetic field from south to north} perpendicularly.
hence, induced emf = Bvl sin90°
= 4 × 10^-5 × 25/3 × 3
= 10^-3 V
if the player is running with rod in horizontal position, then rod doesn't cut earth's magnetic field.
hence, induced emf = Bvlsin0° = 0
hence, option (B) is correct
speed of player , v = 30 km/h = 30 × 5/18 = 25/3 m/s
horizontal component of earth's magnetic field, B , = 4 × 10^-5 T
if the player is running with rod in vertical position towards east then, rod cuts earth magnetic field { as you know, earth's magnetic field from south to north} perpendicularly.
hence, induced emf = Bvl sin90°
= 4 × 10^-5 × 25/3 × 3
= 10^-3 V
if the player is running with rod in horizontal position, then rod doesn't cut earth's magnetic field.
hence, induced emf = Bvlsin0° = 0
hence, option (B) is correct
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