Question

An aeroplane in which the distance between the tips of wings is 50 m is flying horizontally with a speed of 360 km/hr over a place where the vertical components of earth magnetic field is 2.0×10⁻⁴ weber / m². The potential difference between the tips of wings would be
(a) 0.1 V(b) 1.0 V(c) 0.2 V(d) 0.01 V

Answer 1

answer : option (b) 1V

explanation : distance between tips of the wings , l = 50m

speed of aeroplane, v = 360 km/h = 360 × 5/18
= 100 m/s

vertical component of earth's magnetic field , B = 2 × 10^-4 Wb/m²

use formula, $|\xi_{in}|=Blv$

= 2 × 10^-4 Wb/m² × 50m × 100m/s

= (2 × 50 × 100) × 10^-4 V

= 1 V

hence, The potential difference between the tips of wings would be 1V.

Answer 2

Answer:

Induced Emf

e=Bv( subscript)* vl  ( note:  v is subscript of B)

velocity of plane=  3600×1000 /3600 =100 m/s

∴e=2×10 ^−4 ×100×50

=1 V