a playground has the shape of a rectangle, with two semi-circles on its smaller sides as diameters, added to its outside. If the sides of the rectangle are 36m and 24.5m, find the area of the playground.
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Answered by
118
24.5 * 36 =882
24.5/2=r=12.25
area of circle = 22/7*12.25 * 12.25=471.625
882+471.625=1353.625
24.5/2=r=12.25
area of circle = 22/7*12.25 * 12.25=471.625
882+471.625=1353.625
Answered by
132
area of the rectangle =l×b=24.5×36=882m
radius of the semi circle=24.5÷2=12.25m
area of semi circle=(π/2)×12.25×12.25=235.598 sq.m
area of such two semi circle=235.598×2=471.196sq.m
therefore total area of the play ground=471.196+882=1353.196sq.m
radius of the semi circle=24.5÷2=12.25m
area of semi circle=(π/2)×12.25×12.25=235.598 sq.m
area of such two semi circle=235.598×2=471.196sq.m
therefore total area of the play ground=471.196+882=1353.196sq.m
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