A plot is 80m ×60 m.two cross path each 4 m wide are constructed at right angles through the centre of field ,such that each path is parallel to one of the side of the rectangle .find the total area used as path
Answers
Answered by
1
ashbi
Secondary SchoolMath 5+3 pts
A plot is 80m ×60 m.two cross path each 4 m wide are constructed at right angles through the centre of field ,such that each path is parallel to one of the side of the rectangle .find the total area used as path
Ask for details Unfollow Report by Kinjalsanghanee 5 days ago
Answers
ashbi
Ashbi Ambitious
A1: We have,
Length AB = 40 m and breadth BC = 25 m
Area of lawn ABCD = 40 m x 25 m = 1000 m2
Length PQ = (40 + 2 + 2 ) m = 44 m
Breadth QR = ( 25 + 2 + 2 ) m = 29 m
Area of PQRS = 44 m x 29 m = 1276 m2
Now, Area of the path = Area of PQRS – Area of the lawn ABCD
= 1276 m2 – 1000 m2 = 276 m2
Rate of leveling the path = Rs. 8.25 per m2
Cost of leveling the path = Rs.( 8.25 x 276) = Rs. 2277
Secondary SchoolMath 5+3 pts
A plot is 80m ×60 m.two cross path each 4 m wide are constructed at right angles through the centre of field ,such that each path is parallel to one of the side of the rectangle .find the total area used as path
Ask for details Unfollow Report by Kinjalsanghanee 5 days ago
Answers
ashbi
Ashbi Ambitious
A1: We have,
Length AB = 40 m and breadth BC = 25 m
Area of lawn ABCD = 40 m x 25 m = 1000 m2
Length PQ = (40 + 2 + 2 ) m = 44 m
Breadth QR = ( 25 + 2 + 2 ) m = 29 m
Area of PQRS = 44 m x 29 m = 1276 m2
Now, Area of the path = Area of PQRS – Area of the lawn ABCD
= 1276 m2 – 1000 m2 = 276 m2
Rate of leveling the path = Rs. 8.25 per m2
Cost of leveling the path = Rs.( 8.25 x 276) = Rs. 2277
Similar questions