A PLOT IS IN THE FORM OF A RECTANGLE ABCD HAVING SEMI CIRCLE ON BC.IF AB=60M AND BC=28M, FIND THE AREA OF PLOT. THE PROBLEM IS THAT THE BOOK IS SHOWING THE ANSWER AS-1988 square metre AND MY ANSWER IS 1702 square metre PLEASE CHECK.
Answers
Answered by
181
Hi ,
Dimensions of he ABCD rectangular plot ,
AB = 60m ,
BC = 28m ,
i) Area of the ABCD = length×breadth
= 60m × 28m
= 1680 m^2 ---( 1 )
ii) Radius of the semicircle on BC ( r )
= BC / 2
= 28m / 2
= 14m
r = 14m
Area of the semicircle
= ( pi × r ^2)/ 2
= (22 × 14 × 14 )/ ( 2 × 7 )
= 22 × 14
= 308 m^2
Area of the semicircle = 308m^2--( 2 )
Now , Required area = ( 1 ) + ( 2 )
= 1680 m^2 + 308 m^2
= 1988 m^2
I hope this helps you.
Dimensions of he ABCD rectangular plot ,
AB = 60m ,
BC = 28m ,
i) Area of the ABCD = length×breadth
= 60m × 28m
= 1680 m^2 ---( 1 )
ii) Radius of the semicircle on BC ( r )
= BC / 2
= 28m / 2
= 14m
r = 14m
Area of the semicircle
= ( pi × r ^2)/ 2
= (22 × 14 × 14 )/ ( 2 × 7 )
= 22 × 14
= 308 m^2
Area of the semicircle = 308m^2--( 2 )
Now , Required area = ( 1 ) + ( 2 )
= 1680 m^2 + 308 m^2
= 1988 m^2
I hope this helps you.
Answered by
34
Answer:
Area of plot= area of rectangle + area of semicircle
=60×28 +1/2 × 22/7 × 14 ×14
=1680 + 308
=1988square meters
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