Question

The area of parallelogram is p cm2 and the height is q cm. A second parallelogram has equal areabut its base is r cm more than the first. Obtainan expression in terms of p , q and r for height h of the second parallelogram.

Answer 1

let be the base of first triangle be t and hieght of second triangle be h and base b then,
pcm2=QT=BH
BH= (T+ r) * h
 h= QT/T+r

Answer 2

H=qt/r this the answer