Chemistry, asked by Anonymous, 3 months ago

A plot of no.of neutrons (n) against the no.of protons (p) of stable nuclei exhibits upward deviation from linearity for atomic number Z > 20. For an unstable nuclei n/p < 1, the possible mode(s) of decay is : 
1. Beta Emission 
2. neutron emission
3. Orbital Capture
4. Positron Emission ​

Answers

Answered by pratiyabhusagar
0

Answer:

n/p ratio should increase and for that number of neutron should increase and proton should decrease.

oe¹+ 1P¹→ 1 n0. (K-electron capture)

1P ¹→ 1n0+ 1β0. (β+decay)

In both cases the number of neutron increase by 1 and proton decrease by 1.

option:- 3,4

Explanation:

i hope it will be the answer......

Answered by Anonymous
14

 

\: \: \boxed{\boxed{\rm{\mapsto \: \: \:  Question }}}

A plot of no.of neutrons (n) against the no.of protons (p) of stable nuclei exhibits upward deviation from linearity for atomic number Z > 20. For an unstable nuclei n/p < 1, the possible mode(s) of decay is : 

1. Beta Emission 

2. neutron emission

3. Orbital Capture

4. Positron Emission

______________________________________________

\: \: \boxed{\boxed{\rm{\mapsto \: \: \: Firstly \: let's \: understand \: the \: question \: first}}}

In the question it is given that

• A plot of no.of neutrons (n) against the no.of protons (p) of stable nuclei exhibits upward deviation from linearity for atomic number Z > 20.

And the four options are given in which we need to find the -

• an unstable nuclei n/p < 1, the possible mode(s) of decay ?

1. Beta Emission

2. neutron emission

3. Orbital Capture

4. Positron Emission

 

_______________________________________________

\: \: \boxed{\boxed{\rm{\mapsto \: \: \:  Solution }}}

3. Orbital Capture

4. Positron Emission 

_______________________________________________

\: \: \boxed{\boxed{\rm{\mapsto \: \: \: Step \: by \:Step \:  Solution }}}

~ it is given that n/p < 1 which mean number of neutron is less than proton or we can say proton is large in numbers

\: \: \huge\boxed{{\rm{n &lt; p }}}

so let's check the possible modes of decay !

_______________________________________________

1) Beta Emission 

• its happens when neutron change into proton .

 \Longrightarrow \sf  {_0} n ^{1}  \rightarrow{_1} {p}^{1}  + {_ - {_1}}e ^{0}

• By which n/p will further decrease .

• therefore , unstable .

• beta emission is not the possible mode of decay .

\begin{gathered}\begin{gathered}\begin{gathered}\\\;\underline{\boxed{\tt{\odot\;\;Hence,\; Beta \:  Emission is\;\bf{\red{not \: possible}}}}}\end{gathered} \end{gathered}\end{gathered}

2) Neutron Emission

• in Neutral Emission neutron will emit .

• hence , it will decrease neutron in n/p .

• therefore , unstable .

• Neutron Emission is not the possible mode of decay .

\begin{gathered}\begin{gathered}\begin{gathered}\\\;\underline{\boxed{\tt{\odot\;\;Hence,\; Neutron \:  Emission is\;\bf{\red{not \: possible}}}}}\end{gathered} \end{gathered}\end{gathered}

3) Orbital Capture

• its happens when proton capture the electron and changes into neutron .

 \Longrightarrow \sf  {_1} p ^{1}   + {_ - {_1}} {e}^{0}  \rightarrow {_0}n^{1}

• By which n/p will further increase .

• therefore , stable .

• Orbital Capture is the possible mode of decay .

\begin{gathered}\begin{gathered}\begin{gathered}\\\;\underline{\boxed{\tt{\odot\;\;Hence,\; Orbital \:  Capture is\;\bf{\green{possible}}}}}\end{gathered} \end{gathered}\end{gathered}

4. Positron Emission 

• it happens when proton changes into neutron .

 \Longrightarrow \sf  {_1} p ^{1}   \rightarrow {_0}n^{1}  + {_  +  {_1}} {e}^{0}

• if proton will change into neutron then proton will decrease and neutron will increase .

• mean that n/p will further increase .

• therefore , stable .

• Positron Emission is the possible mode of decay .

\begin{gathered}\begin{gathered}\begin{gathered}\\\;\underline{\boxed{\tt{\odot\;\;Hence,\; Positron  \: Emission  is\;\bf{\green{possible}}}}}\end{gathered} \end{gathered}\end{gathered}

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