A plus minus 10 microcoulomb charge of mass 0.2 milligram is placed in an electric field of 500 Newton / Coulomb. Find its velocity after 2 second? ???
Please reply me fast because I have my exam on tomorrow so that I can practice for it please yrr reply me fast
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we can find it with the help of formula F =qE i. e electric intensity formula so put f = ma in this equation so it will become ma = qE now put a = v /t this equation will be mv/t =qE so now put mass is equal to o.2 x 10 ^ -3 g and t = is this equation 2 seconds and E is 500 N C-1 so you will get ans easily
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