A point charge causes an electric flux of -1.0x10 Nm /C to pass through a spherical Gaussian surface of 10cm
radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would
pass the surface ?
(b) What would be the value of point charge ?
Answers
Answered by
13
answer : (a) -1.0 × 10³ Nm²/C (b) -8.854 nC
It has given that a point charge causes an electric flux of -1.0 × 10³ Nm²/C to pass through a spherical Gaussian surface of r = 10cm radius centred on the charge.
(a) electric flux is the ratio of charge enclosed the Gaussian surface to the permittivity of medium.
i.e., Φ = Q/∈_0
it is clear that electric flux doesn't depend on the radius of Gaussian surface.
so, electric flux remains same. i.e., - 1.0 × 10³ Nm²/C
(b) point charge inside the Gaussian surface, Q = Φ∈_0
= -1.0 × 10³ Nm²/C × 8.854 × 10¯¹² C²/Nm²
= -8.854 × 10^-9 C
= -8.854 nC
Similar questions
Hindi,
5 months ago
Math,
5 months ago
English,
10 months ago
English,
10 months ago
Business Studies,
1 year ago