Question

A point charge is located at q1=μc,(2m,1m) and a charge is located at q2= -5μc(-2m,4m) find the force exerted by q1 on q2

Answer 1

Answer:

Explanation:

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Answer 2

Answer:

Explanation:

Correct option is

B

−6.3KV

Step 1: Potential due to q  

1

​

 to q  

2

​

    [Ref. Fig.]

From Figure distance r  

2

​

=5m

At point A

Potential due to q  

1

​

, V  

1

​

=  

r  

1

​

 

Kq  

1

​

 

​

=  

4m

9×10  

9

×(2×10  

−6

C)

​

     

                         ⇒  V  

1

​

=4.5×10  

3

Volts

Potential due to q  

2

​

, V  

2

​

=  

r  

2

​

 

Kq  

2

​

 

​

=  

5m

9×10  

9

×(−6×10  

−6

C)

​

 

                         ⇒  V  

2

​

=−10.8×10  

3

Volts

Step 2: Net Potential at Point (A)

Potential is a scalar quantity

So,           V  

net

​

=V  

1

​

+V  

2

​

 

                        =4.5×10  

3

−10.8×10  

3

=−6.3×10  

3

volts

               V  

net

​

=−6.3KV

Hence, option B is correct.