Question

find the exponential form of 7639.801​

Answer 1

Solution :-

we know that,

• exponential form is writing a number in multiple of powers .

so, In order to write 7639.801 in exponential form multiply each term by their place values we get,

• 7 place value = Thousand = 1000
• 6 place value = Hundred = 100
• 3 place value = Ten = 10
• 9 place value = unit = 1
• 8 place value = Tenths = 1/10
• 0 place value = Hundredths = 1/100
• 1 place value = Thousandths = 1/1000

then, 7639.801 can be written as ,

→ 7639.801 = 7 * 1000 + 6 * 100 + 3 * 10 + 9 * 1 + 8 * (1/10) + 0 * 1/100 + 1 * (1/1000)

now, writing all place values in exponential form as base 10 we get,

→ 7639.801 = 7 * 10³ + 6 * 10² + 3 * 10¹ + 9 * 10⁰ + 8 * 10^(-1) + 0 * 10^(-2) + 1 * 10^(-3)

Learn more :-

(3) निम्न के स्थानीय मान लिखिये-

(अ)43.24

(स)884.20

(ब) 534.34

(द) 178.34

https://brainly.in/question/37666224

Answer 2

Given:

7639.801

To find:

The exponential form

Solution:

7639.801

Multiply each digit with its place value.

$= > 7 \times 1000 = 7000$

$= > 6 \times 100 = 600$

$= > 3 \times 10 = 30$

$= > 9 \times 1 = 9$

$= > 8 \times \dfrac{1}{10} = \dfrac{8}{10}$

$= > 1 \times \dfrac{1}{1000} = \dfrac{1}{1000}$

Expanding by using exponents:

$7000 + 600 + 30 + 9 + \dfrac{8}{10} + 0 + \dfrac{1}{1000}$

$(7 \times {10}^{3} ) + (6 \times {10}^{2}) + (3 \times {10}^{1} ) + 9 + (8 \times {10}^{ - 1} ) + (0) + (1 \times {10}^{ - 3} )$