A point charge moving with velocity
V = (3m/s) i is released in a uniform
electric field E
(ai + bi)
The
subsequent trajectory of the particle will
be
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Answer:
- if there is only electric field,then the charge will have a straight line path.and it doesn't depends on velocity, because, force on the charge is given by,F=qE
- but,if there is a magnetic field,then it may have circular or helical motions, because,force on a point charge in magnetic field is given by, F=q(v×B)
where v is the velocity of the charge..!
hope it helps..!!
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