Physics, asked by krishvaghasiya27, 8 months ago

A point charge of magnitude 8.85×10-¹² is placed at the centre of cube. The electric flux passing through the cube is

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Answered by nidhiakara
11

Answer:

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Answered by Jasleen0599
4

Given:

The magnitude of charge = 8.85 × 10⁻¹² C

To Find:

The electric flux passing through the cube.

Calculation:

- According to Gauss's Law, the total electric flux is given by the formula:

Electric flux = Total charge / Permittivity of free space

⇒ φ = q / ε₀

⇒ φ = 8.85 × 10⁻¹² / 8.85 × 10⁻¹²

⇒ φ = 1 N m² C⁻¹

So, the electric flux passing through the cube is  1 N m² C⁻¹.

(Note: If the flux passing through each faced is asked, we divide it by 6)

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