Question

A point charge of magnitude 8.85×10 to the power-12 us placed bat center of cube the electric flux Passing through one face is

Answer 1

Electric flux passing through one face of the cube = 1/6 Nm2/C

Explanation:

According to Gauss's law, the electric flux ϕ enclosed by the total surface of the cube is  q/£.

ϕ = q/£ for 6 faces of the cube.

So the flux for one face ϕ / 6  = q / 6£

Given q = 8.85 * 10^-12 C

And the permittivity of free space (£) is a physical constant equal to approximately 8.85 * 10-12.

So q / 6£ = 8.85 * 10^-12 / (6 * (8.85 * 10^-12) = 1/6

Therefore electric flux passing through one face of the cube = 1/6 Nm2/C