Question

a point charge q =8.85 ×10^-9 cis placed at (0,d,0) where d=1m . an insulating surface abca is on the x -z plane​

Answer 1

Answer:

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Answer 2

7.038*10^-7N

Explanation:

The force between the given electron and an electron on the origin can be calculated as under:

Force = $Ke*(q1*q2)/r^{2}$

Ke = Coulomb's constant = $8.987 * 10^9$ $Nm^{2}/C^{2}$

q1 = q2 = $8.85*10^-9$ C

r = 1m

Plugging these values into the above formula we get

Force = $7.038*10^-7$ Newtons