Question

A point charge Q is enclosed in a Gaussian spherical surface of radius R. If radius is halved, then electric flux will ​

Answer 1

Explanation:

By Gauss's law, electric flux through a surface is ϕ=ϵ0Qen where Qen= charge enclosed by the surface. Thus, the electric flux is depends only on the charge enclosed by the surface. It is independent of radius of surface. Hence, when radius is doubled so the flux will not change.

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Answer 2

Answer:

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Explanation:

When dipole moment vector is parallel to electric field vector.