Question

the capillary rise at 20 c in clean glass tube of 1 mm diameter containing water is approx.?

Answer 1

Answer:

The capillary rise = 29.56 mm

Explanation:

h = 4 a cos Ф / p g d

Here Ф = 0° for water and glass, surface tension = 0.0725 N/m

h = 4 x 0.0725 x cos 0 / (1000 x 9.81 x 10⁻³)

h = 0.02956 m

h = 29.56 mm  = the capillary rise

Answer 2

Answer:

The capillary rise is approx 30 mm.

Explanation:

Given that,

Diameter = 1 mm

We need to calculate the height of the capillary

$h = \dfrac{4Tcos\theta}{\rho g d}$

Where,

H = height of capillary

$\rho$=density of water

g = acceleration due to gravity

d = diameter

For water and glass,

Contact angle = 0°

Surface tension $T= 0.0725\ N/m$

Put the value into the formula

$h = \dfrac{4\times0.0725}{1000\times9.8\times1\times10^{-3}}$

$h = 0.02956\ m$

$h = 29.56\approx 30\ mm$

Hence, The capillary rise is approx 30 mm.