Question

Find the zeroes :-

$2 {x}^{2} - 2 \sqrt{2} x - 3$

Answer 1

$2 {x}^{2} - 2 \sqrt{2} x - 3 \\ \\ = 2 {x}^{2} - 3 \sqrt{2} x + \sqrt{2} x - 3 \\ \\ = \sqrt{2} x( \sqrt{2} x - 3) + 1( \sqrt{2} x - 3) \\ \\ = ( \sqrt{2} x - 3)( \sqrt{2} x + 1)$

Zeroes are :-

3 / root2 and - 1 / root2

Answer 2

Zeroes are :-

3 / root2 and - 1 / root2