Question

A point charge q is held at a distance 2a from the
centre of an isolated, uncharged conductance
sphere of radius a. The potential of the sphere is
(a) ???? (b) ????
8????εₒ???? 4????εₒ????
(c) ???? (d) zero
2????εₒ????

Answer 1

Explanation:

Charge =q

distance =2R

radius =R

V= Potential at centre of the shell due to charge induced on shell.

As the electric field inside a conductor is zero. The electrostatic potential is constant it. The potential at centre will be the potential of entire conductor. The entire charge of conductor is on surface N.

Now, $$V=\dfrac { -1 }{ 4\pi { \epsilon }_{ 0 } } \dfrac { q }{ R } $$

The (−Ve) sign due to spherical shell of centre (inside).

Answer 2

Answer :- Option D.....