A sphere of radius R has uniform volume charge
density. The electric potential at a points (r < R) is
(a) due to the charge inside a sphere of radius r only
(b) due to the entire charge of the sphere
(c) due to the charge in the spherical shell of
inner and outer radii r and R, only
(d) independent of r
Answers
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0
Explanation:
By Gauss's law the electric field at a distance r is E.4πr
2
=
ϵ
0
Q
en
or $$E=\dfrac{Q_{en}}{4\pi\epsilon_0 r^2}$$ where Q
en
= charge inside sphere of radius r.
As the potential V=−∫Edr so the electric potential at r due to charge inside a sphere of radius r only.
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